[프로그래머스] ⭐⭐ 오랜 기간 보호한 동물(1) (MySQL)
문제


코드
ver(1) - LEFT JOIN 사용
SELECT A.NAME, A.DATETIME
FROM ANIMAL_INS AS A
LEFT
JOIN ANIMAL_OUTS AS B
ON A.ANIMAL_ID = B.ANIMAL_ID
WHERE B.ANIMAL_ID IS NULL
ORDER BY A.DATETIME
LIMIT 3


SELECT A.NAME, A.DATETIME
FROM ANIMAL_INS AS A
LEFT
JOIN ANIMAL_OUTS AS B
ON A.ANIMAL_ID = B.ANIMAL_ID
WHERE B.ANIMAL_ID IS NULL
ORDER BY A.DATETIME
LIMIT 3
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